aesara.tensor.nlinalg.tensorsolve#

aesara.tensor.nlinalg.tensorsolve(a, b, axes=None)[source]#

Aesara utilization of numpy.linalg.tensorsolve.

Solve the tensor equation a x = b for x. It is assumed that all indices of x are summed over in the product, together with the rightmost indices of a, as is done in, for example, tensordot(a, x, axes=len(b.shape)).

Parameters:

  • a (array_like) – Coefficient tensor, of shape b.shape + Q. Q, a tuple, equals the shape of that sub-tensor of a consisting of the appropriate number of its rightmost indices, and must be such that prod(Q) == prod(b.shape) (in which sense a is said to be ‘square’).

  • b (array_like) – Right-hand tensor, which can be of any shape.

  • axes (tuple of ints, optional) – Axes in a to reorder to the right, before inversion. If None (default), no reordering is done.

Returns:

x

Return type:

ndarray, shape Q

Raises:

LinAlgError – If a is singular or not ‘square’ (in the above sense).